Optimal. Leaf size=202 \[ -\frac {3 i \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^4}-\frac {3 i \text {Li}_4\left (e^{2 i (a+b x)}\right )}{4 b^4}-\frac {3 x \text {Li}_3\left (e^{2 i (a+b x)}\right )}{2 b^3}+\frac {3 x \log \left (1-e^{2 i (a+b x)}\right )}{b^3}+\frac {3 i x^2 \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {x^3 \cot ^2(a+b x)}{2 b}-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4} \]
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Rubi [A] time = 0.30, antiderivative size = 202, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 10, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.833, Rules used = {3720, 3717, 2190, 2279, 2391, 30, 2531, 6609, 2282, 6589} \[ \frac {3 i x^2 \text {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x \text {PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^3}-\frac {3 i \text {PolyLog}\left (2,e^{2 i (a+b x)}\right )}{2 b^4}-\frac {3 i \text {PolyLog}\left (4,e^{2 i (a+b x)}\right )}{4 b^4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}+\frac {3 x \log \left (1-e^{2 i (a+b x)}\right )}{b^3}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {x^3 \cot ^2(a+b x)}{2 b}-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4} \]
Antiderivative was successfully verified.
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Rule 30
Rule 2190
Rule 2279
Rule 2282
Rule 2391
Rule 2531
Rule 3717
Rule 3720
Rule 6589
Rule 6609
Rubi steps
\begin {align*} \int x^3 \cot ^3(a+b x) \, dx &=-\frac {x^3 \cot ^2(a+b x)}{2 b}+\frac {3 \int x^2 \cot ^2(a+b x) \, dx}{2 b}-\int x^3 \cot (a+b x) \, dx\\ &=\frac {i x^4}{4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \cot ^2(a+b x)}{2 b}+2 i \int \frac {e^{2 i (a+b x)} x^3}{1-e^{2 i (a+b x)}} \, dx+\frac {3 \int x \cot (a+b x) \, dx}{b^2}-\frac {3 \int x^2 \, dx}{2 b}\\ &=-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \cot ^2(a+b x)}{2 b}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {(6 i) \int \frac {e^{2 i (a+b x)} x}{1-e^{2 i (a+b x)}} \, dx}{b^2}+\frac {3 \int x^2 \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \cot ^2(a+b x)}{2 b}+\frac {3 x \log \left (1-e^{2 i (a+b x)}\right )}{b^3}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}+\frac {3 i x^2 \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 \int \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b^3}-\frac {(3 i) \int x \text {Li}_2\left (e^{2 i (a+b x)}\right ) \, dx}{b^2}\\ &=-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \cot ^2(a+b x)}{2 b}+\frac {3 x \log \left (1-e^{2 i (a+b x)}\right )}{b^3}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}+\frac {3 i x^2 \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x \text {Li}_3\left (e^{2 i (a+b x)}\right )}{2 b^3}+\frac {(3 i) \operatorname {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^4}+\frac {3 \int \text {Li}_3\left (e^{2 i (a+b x)}\right ) \, dx}{2 b^3}\\ &=-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \cot ^2(a+b x)}{2 b}+\frac {3 x \log \left (1-e^{2 i (a+b x)}\right )}{b^3}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {3 i \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^4}+\frac {3 i x^2 \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x \text {Li}_3\left (e^{2 i (a+b x)}\right )}{2 b^3}-\frac {(3 i) \operatorname {Subst}\left (\int \frac {\text {Li}_3(x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{4 b^4}\\ &=-\frac {3 i x^2}{2 b^2}-\frac {x^3}{2 b}+\frac {i x^4}{4}-\frac {3 x^2 \cot (a+b x)}{2 b^2}-\frac {x^3 \cot ^2(a+b x)}{2 b}+\frac {3 x \log \left (1-e^{2 i (a+b x)}\right )}{b^3}-\frac {x^3 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac {3 i \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^4}+\frac {3 i x^2 \text {Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}-\frac {3 x \text {Li}_3\left (e^{2 i (a+b x)}\right )}{2 b^3}-\frac {3 i \text {Li}_4\left (e^{2 i (a+b x)}\right )}{4 b^4}\\ \end {align*}
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Mathematica [B] time = 6.81, size = 461, normalized size = 2.28 \[ \frac {3 x^2 \csc (a) \sin (b x) \csc (a+b x)}{2 b^2}-\frac {3 \csc (a) \sec (a) \left (b^2 x^2 e^{i \tan ^{-1}(\tan (a))}+\frac {\tan (a) \left (i \text {Li}_2\left (e^{2 i \left (b x+\tan ^{-1}(\tan (a))\right )}\right )+i b x \left (2 \tan ^{-1}(\tan (a))-\pi \right )-2 \left (\tan ^{-1}(\tan (a))+b x\right ) \log \left (1-e^{2 i \left (\tan ^{-1}(\tan (a))+b x\right )}\right )+2 \tan ^{-1}(\tan (a)) \log \left (\sin \left (\tan ^{-1}(\tan (a))+b x\right )\right )-\pi \log \left (1+e^{-2 i b x}\right )+\pi \log (\cos (b x))\right )}{\sqrt {\tan ^2(a)+1}}\right )}{2 b^4 \sqrt {\sec ^2(a) \left (\sin ^2(a)+\cos ^2(a)\right )}}+\frac {e^{i a} \csc (a) \left (e^{-2 i a} b^4 x^4+2 i \left (1-e^{-2 i a}\right ) b^3 x^3 \log \left (1-e^{-i (a+b x)}\right )+2 i \left (1-e^{-2 i a}\right ) b^3 x^3 \log \left (1+e^{-i (a+b x)}\right )-6 e^{-2 i a} \left (-1+e^{2 i a}\right ) \left (b^2 x^2 \text {Li}_2\left (-e^{-i (a+b x)}\right )-2 i b x \text {Li}_3\left (-e^{-i (a+b x)}\right )-2 \text {Li}_4\left (-e^{-i (a+b x)}\right )\right )-6 e^{-2 i a} \left (-1+e^{2 i a}\right ) \left (b^2 x^2 \text {Li}_2\left (e^{-i (a+b x)}\right )-2 i b x \text {Li}_3\left (e^{-i (a+b x)}\right )-2 \text {Li}_4\left (e^{-i (a+b x)}\right )\right )\right )}{4 b^4}-\frac {x^3 \csc ^2(a+b x)}{2 b}-\frac {1}{4} x^4 \cot (a) \]
Warning: Unable to verify antiderivative.
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fricas [C] time = 2.05, size = 565, normalized size = 2.80 \[ \frac {8 \, b^{3} x^{3} + 12 \, b^{2} x^{2} \sin \left (2 \, b x + 2 \, a\right ) + {\left (-6 i \, b^{2} x^{2} + {\left (6 i \, b^{2} x^{2} - 6 i\right )} \cos \left (2 \, b x + 2 \, a\right ) + 6 i\right )} {\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) + {\left (6 i \, b^{2} x^{2} + {\left (-6 i \, b^{2} x^{2} + 6 i\right )} \cos \left (2 \, b x + 2 \, a\right ) - 6 i\right )} {\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right ) - 4 \, {\left (a^{3} - {\left (a^{3} - 3 \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - 3 \, a\right )} \log \left (-\frac {1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) + \frac {1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac {1}{2}\right ) - 4 \, {\left (a^{3} - {\left (a^{3} - 3 \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - 3 \, a\right )} \log \left (-\frac {1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) - \frac {1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac {1}{2}\right ) + 4 \, {\left (b^{3} x^{3} + a^{3} - 3 \, b x - {\left (b^{3} x^{3} + a^{3} - 3 \, b x - 3 \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - 3 \, a\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) + 4 \, {\left (b^{3} x^{3} + a^{3} - 3 \, b x - {\left (b^{3} x^{3} + a^{3} - 3 \, b x - 3 \, a\right )} \cos \left (2 \, b x + 2 \, a\right ) - 3 \, a\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) + {\left (-3 i \, \cos \left (2 \, b x + 2 \, a\right ) + 3 i\right )} {\rm polylog}\left (4, \cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) + {\left (3 i \, \cos \left (2 \, b x + 2 \, a\right ) - 3 i\right )} {\rm polylog}\left (4, \cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right ) - 6 \, {\left (b x \cos \left (2 \, b x + 2 \, a\right ) - b x\right )} {\rm polylog}\left (3, \cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) - 6 \, {\left (b x \cos \left (2 \, b x + 2 \, a\right ) - b x\right )} {\rm polylog}\left (3, \cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right )}{8 \, {\left (b^{4} \cos \left (2 \, b x + 2 \, a\right ) - b^{4}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{3} \cot \left (b x + a\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 1.06, size = 444, normalized size = 2.20 \[ \frac {3 i \polylog \left (2, {\mathrm e}^{i \left (b x +a \right )}\right ) x^{2}}{b^{2}}+\frac {x^{2} \left (2 b x \,{\mathrm e}^{2 i \left (b x +a \right )}-3 i {\mathrm e}^{2 i \left (b x +a \right )}+3 i\right )}{b^{2} \left ({\mathrm e}^{2 i \left (b x +a \right )}-1\right )^{2}}+\frac {2 i a^{3} x}{b^{3}}+\frac {3 i \polylog \left (2, -{\mathrm e}^{i \left (b x +a \right )}\right ) x^{2}}{b^{2}}-\frac {6 i a x}{b^{3}}-\frac {3 i x^{2}}{b^{2}}+\frac {3 \ln \left ({\mathrm e}^{i \left (b x +a \right )}+1\right ) x}{b^{3}}+\frac {3 \ln \left (1-{\mathrm e}^{i \left (b x +a \right )}\right ) x}{b^{3}}+\frac {6 a \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {3 a \ln \left ({\mathrm e}^{i \left (b x +a \right )}-1\right )}{b^{4}}+\frac {3 a \ln \left (1-{\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {6 \polylog \left (3, -{\mathrm e}^{i \left (b x +a \right )}\right ) x}{b^{3}}-\frac {3 i \polylog \left (2, {\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {3 i \polylog \left (2, -{\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {3 i a^{2}}{b^{4}}+\frac {a^{3} \ln \left ({\mathrm e}^{i \left (b x +a \right )}-1\right )}{b^{4}}-\frac {\ln \left (1-{\mathrm e}^{i \left (b x +a \right )}\right ) a^{3}}{b^{4}}-\frac {\ln \left (1-{\mathrm e}^{i \left (b x +a \right )}\right ) x^{3}}{b}+\frac {3 i a^{4}}{2 b^{4}}-\frac {2 a^{3} \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {6 \polylog \left (3, {\mathrm e}^{i \left (b x +a \right )}\right ) x}{b^{3}}-\frac {\ln \left ({\mathrm e}^{i \left (b x +a \right )}+1\right ) x^{3}}{b}-\frac {6 i \polylog \left (4, -{\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}-\frac {6 i \polylog \left (4, {\mathrm e}^{i \left (b x +a \right )}\right )}{b^{4}}+\frac {i x^{4}}{4} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.75, size = 1970, normalized size = 9.75 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int x^3\,{\mathrm {cot}\left (a+b\,x\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{3} \cot ^{3}{\left (a + b x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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